(6x-34)+(2x+80)+(4x-10)=180

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Solution for (6x-34)+(2x+80)+(4x-10)=180 equation: 



(6x-34)+(2x+80)+(4x-10)=180

We move all terms to the left:

(6x-34)+(2x+80)+(4x-10)-(180)=0

We get rid of parentheses

6x+2x+4x-34+80-10-180=0

We add all the numbers together, and all the variables

12x-144=0

We move all terms containing x to the left, all other terms to the right

12x=144

x=144/12

x=12

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