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4/3n-2n=3
We move all terms to the left:
4/3n-2n-(3)=0
Domain of the equation: 3n!=0We add all the numbers together, and all the variables
n!=0/3
n!=0
n∈R
-2n+4/3n-3=0
We multiply all the terms by the denominator
-2n*3n-3*3n+4=0
Wy multiply elements
-6n^2-9n+4=0
a = -6; b = -9; c = +4;
Δ = b2-4ac
Δ = -92-4·(-6)·4
Δ = 177
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9)-\sqrt{177}}{2*-6}=\frac{9-\sqrt{177}}{-12} $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9)+\sqrt{177}}{2*-6}=\frac{9+\sqrt{177}}{-12} $
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