-3x-4(4x-8)=(-8x-1)

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Solution for -3x-4(4x-8)=(-8x-1) equation: 



-3x-4(4x-8)=(-8x-1)

We move all terms to the left:

-3x-4(4x-8)-((-8x-1))=0

We multiply parentheses

-3x-16x-((-8x-1))+32=0



We calculate terms in parentheses: -((-8x-1)), so:

(-8x-1)

We get rid of parentheses

-8x-1

Back to the equation:

-(-8x-1)



We add all the numbers together, and all the variables

-19x-(-8x-1)+32=0

We get rid of parentheses

-19x+8x+1+32=0

We add all the numbers together, and all the variables

-11x+33=0

We move all terms containing x to the left, all other terms to the right

-11x=-33

x=-33/-11

x=+3

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