2(m(2)+4(2))=24

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Solution for 2(m(2)+4(2))=24 equation: 



2(m(2)+4(2))=24

We move all terms to the left:

2(m(2)+4(2))-(24)=0

We add all the numbers together, and all the variables

2(+m^2+42)-24=0

We multiply parentheses

2m^2+84-24=0

We add all the numbers together, and all the variables

2m^2+60=0

a = 2; b = 0; c = +60;
Δ = b2-4ac
Δ = 02-4·2·60
Δ = -480
Delta is less than zero, so there is no solution for the equation

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