(4y+3)=(2y-5)

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Solution for (4y+3)=(2y-5) equation: 



(4y+3)=(2y-5)

We move all terms to the left:

(4y+3)-((2y-5))=0

We get rid of parentheses

4y-((2y-5))+3=0



We calculate terms in parentheses: -((2y-5)), so:

(2y-5)

We get rid of parentheses

2y-5

Back to the equation:

-(2y-5)



We get rid of parentheses

4y-2y+5+3=0

We add all the numbers together, and all the variables

2y+8=0

We move all terms containing y to the left, all other terms to the right

2y=-8

y=-8/2

y=-4

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