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-3x(x-5)+6x=4
We move all terms to the left:
-3x(x-5)+6x-(4)=0
We add all the numbers together, and all the variables
6x-3x(x-5)-4=0
We multiply parentheses
-3x^2+6x+15x-4=0
We add all the numbers together, and all the variables
-3x^2+21x-4=0
a = -3; b = 21; c = -4;
Δ = b2-4ac
Δ = 212-4·(-3)·(-4)
Δ = 393
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(21)-\sqrt{393}}{2*-3}=\frac{-21-\sqrt{393}}{-6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(21)+\sqrt{393}}{2*-3}=\frac{-21+\sqrt{393}}{-6} $
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