-3n-3n=3(n+2)+3(3n-2)

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Solution for -3n-3n=3(n+2)+3(3n-2) equation: 



-3n-3n=3(n+2)+3(3n-2)

We move all terms to the left:

-3n-3n-(3(n+2)+3(3n-2))=0

We add all the numbers together, and all the variables

-6n-(3(n+2)+3(3n-2))=0



We calculate terms in parentheses: -(3(n+2)+3(3n-2)), so:

3(n+2)+3(3n-2)

We multiply parentheses

3n+9n+6-6

We add all the numbers together, and all the variables

12n

Back to the equation:

-(12n)



We add all the numbers together, and all the variables

-18n=0

n=0/-18

n=0

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