(6x-5)/7=(-4x-5)/12

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Solution for (6x-5)/7=(-4x-5)/12 equation: 



(6x-5)/7=(-4x-5)/12

We move all terms to the left:

(6x-5)/7-((-4x-5)/12)=0

We calculate fractions


6x/()+(-((-4x-5)*7)/()=0



We calculate terms in parentheses: +(-((-4x-5)*7)/(), so:

-((-4x-5)*7)/(

We multiply all the terms by the denominator


-((-4x-5)*7)



We calculate terms in parentheses: -((-4x-5)*7), so:

(-4x-5)*7

We multiply parentheses

-28x-35

Back to the equation:

-(-28x-35)



We get rid of parentheses

28x+35

Back to the equation:

+(28x+35)



We get rid of parentheses

6x/()+28x+35=0

We multiply all the terms by the denominator


6x+28x*()+35*()=0

We add all the numbers together, and all the variables

6x+28x*()=0

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