-3h(h-8)=0

Solution for -3h(h-8)=0 equation:

-3h(h-8)=0

We multiply parentheses

-3h^2+24h=0

a = -3; b = 24; c = 0;
Δ = b2-4ac
Δ = 242-4·(-3)·0
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{576}=24$
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(24)-24}{2*-3}=\frac{-48}{-6}
=+8
$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(24)+24}{2*-3}=\frac{0}{-6}
=0
$