T1=n2+2n+3

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Solution for T1=n2+2n+3 equation: 



1=T2+2T+3

We move all terms to the left:

1-(T2+2T+3)=0

We add all the numbers together, and all the variables

-(+T^2+2T+3)+1=0

We get rid of parentheses

-T^2-2T-3+1=0

We add all the numbers together, and all the variables

-1T^2-2T-2=0

a = -1; b = -2; c = -2;
Δ = b2-4ac
Δ = -22-4·(-1)·(-2)
Δ = -4
Delta is less than zero, so there is no solution for the equation

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