1=n2+2n+

Solution for 1=n2+2n+ equation:

1=n2+2n+

We move all terms to the left:

1-(n2+2n+)=0

We add all the numbers together, and all the variables

-(+n^2+2n+)+1=0

We get rid of parentheses

-n^2-2n+1-=0

We add all the numbers together, and all the variables

-1n^2-2n=0

a = -1; b = -2; c = 0;
Δ = b2-4ac
Δ = -22-4·(-1)·0
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-2}{2*-1}=\frac{0}{-2}
=0
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+2}{2*-1}=\frac{4}{-2}
=-2
$