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-36+29p=-7p^2-7p
We move all terms to the left:
-36+29p-(-7p^2-7p)=0
We get rid of parentheses
7p^2+7p+29p-36=0
We add all the numbers together, and all the variables
7p^2+36p-36=0
a = 7; b = 36; c = -36;
Δ = b2-4ac
Δ = 362-4·7·(-36)
Δ = 2304
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2304}=48$$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(36)-48}{2*7}=\frac{-84}{14} =-6 $$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(36)+48}{2*7}=\frac{12}{14} =6/7 $
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