35v2-21v-28=8v

Solution for 35v2-21v-28=8v equation:

35v^2-21v-28=8v

We move all terms to the left:

35v^2-21v-28-(8v)=0

We add all the numbers together, and all the variables

35v^2-29v-28=0

a = 35; b = -29; c = -28;
Δ = b2-4ac
Δ = -292-4·35·(-28)
Δ = 4761
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4761}=69$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-29)-69}{2*35}=\frac{-40}{70}
=-4/7
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-29)+69}{2*35}=\frac{98}{70}
=1+2/5
$