10-5x=3(x-4)-2(x-4)-2(x+7)

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Solution for 10-5x=3(x-4)-2(x-4)-2(x+7) equation: 



10-5x=3(x-4)-2(x-4)-2(x+7)

We move all terms to the left:

10-5x-(3(x-4)-2(x-4)-2(x+7))=0



We calculate terms in parentheses: -(3(x-4)-2(x-4)-2(x+7)), so:

3(x-4)-2(x-4)-2(x+7)

We multiply parentheses

3x-2x-2x-12+8-14

We add all the numbers together, and all the variables

-1x-18

Back to the equation:

-(-1x-18)



We get rid of parentheses

-5x+1x+18+10=0

We add all the numbers together, and all the variables

-4x+28=0

We move all terms containing x to the left, all other terms to the right

-4x=-28

x=-28/-4

x=+7

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