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-31+-4=-5+-5(1+5x)
We move all terms to the left:
-31+-4-(-5+-5(1+5x))=0
We add all the numbers together, and all the variables
-(-5+-5(5x+1))-31-4+=0
We add all the numbers together, and all the variables
-(-5+-5(5x+1))=0
We use the square of the difference formula
-(-5-5(5x+1))=0
We calculate terms in parentheses: -(-5-5(5x+1)), so:We get rid of parentheses
-5-5(5x+1)
determiningTheFunctionDomain -5(5x+1)-5
We multiply parentheses
-25x-5-5
We add all the numbers together, and all the variables
-25x-10
Back to the equation:
-(-25x-10)
25x+10=0
We move all terms containing x to the left, all other terms to the right
25x=-10
x=-10/25
x=-2/5
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