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6-2x(5x+1)=3
We move all terms to the left:
6-2x(5x+1)-(3)=0
We add all the numbers together, and all the variables
-2x(5x+1)+3=0
We multiply parentheses
-10x^2-2x+3=0
a = -10; b = -2; c = +3;
Δ = b2-4ac
Δ = -22-4·(-10)·3
Δ = 124
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{124}=\sqrt{4*31}=\sqrt{4}*\sqrt{31}=2\sqrt{31}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-2\sqrt{31}}{2*-10}=\frac{2-2\sqrt{31}}{-20} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+2\sqrt{31}}{2*-10}=\frac{2+2\sqrt{31}}{-20} $
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