4z+10=12z-102

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Solution for 4z+10=12z-102 equation:



4z+10=12z-102
We move all terms to the left:
4z+10-(12z-102)=0
We get rid of parentheses
4z-12z+102+10=0
We add all the numbers together, and all the variables
-8z+112=0
We move all terms containing z to the left, all other terms to the right
-8z=-112
z=-112/-8
z=+14

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