-3(z+2)=6

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Solution for -3(z+2)=6 equation: 



-3(z+2)=6

We move all terms to the left:

-3(z+2)-(6)=0

We multiply parentheses

-3z-6-6=0

We add all the numbers together, and all the variables

-3z-12=0

We move all terms containing z to the left, all other terms to the right

-3z=12

z=12/-3

z=-4

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