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(8x-5)=(5x+15)+(40)
We move all terms to the left:
(8x-5)-((5x+15)+(40))=0
We get rid of parentheses
8x-((5x+15)+40)-5=0
We calculate terms in parentheses: -((5x+15)+40), so:We get rid of parentheses
(5x+15)+40
We get rid of parentheses
5x+15+40
We add all the numbers together, and all the variables
5x+55
Back to the equation:
-(5x+55)
8x-5x-55-5=0
We add all the numbers together, and all the variables
3x-60=0
We move all terms containing x to the left, all other terms to the right
3x=60
x=60/3
x=20
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