(3r-8)(94r+3)=0

Solution for (3r-8)(94r+3)=0 equation:

(3r-8)(94r+3)=0

We multiply parentheses ..

(+282r^2+9r-752r-24)=0

We get rid of parentheses

282r^2+9r-752r-24=0

We add all the numbers together, and all the variables

282r^2-743r-24=0

a = 282; b = -743; c = -24;
Δ = b2-4ac
Δ = -7432-4·282·(-24)
Δ = 579121
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{579121}=761$
$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-743)-761}{2*282}=\frac{-18}{564}
=-3/94
$
$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-743)+761}{2*282}=\frac{1504}{564}
=2+2/3
$