-3(u+2)=2u-2+2(2u+1)

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Solution for -3(u+2)=2u-2+2(2u+1) equation: 



-3(u+2)=2u-2+2(2u+1)

We move all terms to the left:

-3(u+2)-(2u-2+2(2u+1))=0

We multiply parentheses

-3u-(2u-2+2(2u+1))-6=0



We calculate terms in parentheses: -(2u-2+2(2u+1)), so:

2u-2+2(2u+1)

determiningTheFunctionDomain
2u+2(2u+1)-2

We multiply parentheses

2u+4u+2-2

We add all the numbers together, and all the variables

6u

Back to the equation:

-(6u)



We add all the numbers together, and all the variables

-9u-6=0

We move all terms containing u to the left, all other terms to the right

-9u=6

u=6/-9

u=-2/3

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