3,4(x-1)-1,2(2x-2)=7(0,5-x)+2(2,25+3x)

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Solution for 3,4(x-1)-1,2(2x-2)=7(0,5-x)+2(2,25+3x) equation: 



3.4(x-1)-1.2(2x-2)=7(0.5-x)+2(2.25+3x)

We move all terms to the left:

3.4(x-1)-1.2(2x-2)-(7(0.5-x)+2(2.25+3x))=0

We add all the numbers together, and all the variables

3.4(x-1)-1.2(2x-2)-(7(-1x+0.5)+2(3x+2.25))=0

We multiply parentheses

3.4x-2.4x-(7(-1x+0.5)+2(3x+2.25))-3.4+2.4=0



We calculate terms in parentheses: -(7(-1x+0.5)+2(3x+2.25)), so:

7(-1x+0.5)+2(3x+2.25)

We multiply parentheses

-7x+6x+3.5+4.5

We add all the numbers together, and all the variables

-1x+8

Back to the equation:

-(-1x+8)



We add all the numbers together, and all the variables

x-(-1x+8)-1=0

We get rid of parentheses

x+1x-8-1=0

We add all the numbers together, and all the variables

2x-9=0

We move all terms containing x to the left, all other terms to the right

2x=9

x=9/2

x=4+1/2

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