4x+2-2(-6x-3)=2(x-4)

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Solution for 4x+2-2(-6x-3)=2(x-4) equation: 



4x+2-2(-6x-3)=2(x-4)

We move all terms to the left:

4x+2-2(-6x-3)-(2(x-4))=0

We multiply parentheses

4x+12x-(2(x-4))+6+2=0



We calculate terms in parentheses: -(2(x-4)), so:

2(x-4)

We multiply parentheses

2x-8

Back to the equation:

-(2x-8)



We add all the numbers together, and all the variables

16x-(2x-8)+8=0

We get rid of parentheses

16x-2x+8+8=0

We add all the numbers together, and all the variables

14x+16=0

We move all terms containing x to the left, all other terms to the right

14x=-16

x=-16/14

x=-1+1/7

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