-3(5x-2)+2x=3(3-2x)+7

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Solution for -3(5x-2)+2x=3(3-2x)+7 equation: 



-3(5x-2)+2x=3(3-2x)+7

We move all terms to the left:

-3(5x-2)+2x-(3(3-2x)+7)=0

We add all the numbers together, and all the variables

-3(5x-2)+2x-(3(-2x+3)+7)=0

We add all the numbers together, and all the variables

2x-3(5x-2)-(3(-2x+3)+7)=0

We multiply parentheses

2x-15x-(3(-2x+3)+7)+6=0



We calculate terms in parentheses: -(3(-2x+3)+7), so:

3(-2x+3)+7

We multiply parentheses

-6x+9+7

We add all the numbers together, and all the variables

-6x+16

Back to the equation:

-(-6x+16)



We add all the numbers together, and all the variables

-13x-(-6x+16)+6=0

We get rid of parentheses

-13x+6x-16+6=0

We add all the numbers together, and all the variables

-7x-10=0

We move all terms containing x to the left, all other terms to the right

-7x=10

x=10/-7

x=-1+3/7

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