-3(3z+2)=4(3z+1)

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Solution for -3(3z+2)=4(3z+1) equation: 



-3(3z+2)=4(3z+1)

We move all terms to the left:

-3(3z+2)-(4(3z+1))=0

We multiply parentheses

-9z-(4(3z+1))-6=0



We calculate terms in parentheses: -(4(3z+1)), so:

4(3z+1)

We multiply parentheses

12z+4

Back to the equation:

-(12z+4)



We get rid of parentheses

-9z-12z-4-6=0

We add all the numbers together, and all the variables

-21z-10=0

We move all terms containing z to the left, all other terms to the right

-21z=10

z=10/-21

z=-10/21

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