3(4z-1)=4(2z+1)

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Solution for 3(4z-1)=4(2z+1) equation: 



3(4z-1)=4(2z+1)

We move all terms to the left:

3(4z-1)-(4(2z+1))=0

We multiply parentheses

12z-(4(2z+1))-3=0



We calculate terms in parentheses: -(4(2z+1)), so:

4(2z+1)

We multiply parentheses

8z+4

Back to the equation:

-(8z+4)



We get rid of parentheses

12z-8z-4-3=0

We add all the numbers together, and all the variables

4z-7=0

We move all terms containing z to the left, all other terms to the right

4z=7

z=7/4

z=1+3/4

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