2(2z-1)=-3(3z+2)

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Solution for 2(2z-1)=-3(3z+2) equation: 



2(2z-1)=-3(3z+2)

We move all terms to the left:

2(2z-1)-(-3(3z+2))=0

We multiply parentheses

4z-(-3(3z+2))-2=0



We calculate terms in parentheses: -(-3(3z+2)), so:

-3(3z+2)

We multiply parentheses

-9z-6

Back to the equation:

-(-9z-6)



We get rid of parentheses

4z+9z+6-2=0

We add all the numbers together, and all the variables

13z+4=0

We move all terms containing z to the left, all other terms to the right

13z=-4

z=-4/13

z=-4/13

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