-3(3y+4)-10=6(y+5)+3y

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Solution for -3(3y+4)-10=6(y+5)+3y equation: 



-3(3y+4)-10=6(y+5)+3y

We move all terms to the left:

-3(3y+4)-10-(6(y+5)+3y)=0

We multiply parentheses

-9y-(6(y+5)+3y)-12-10=0



We calculate terms in parentheses: -(6(y+5)+3y), so:

6(y+5)+3y

We add all the numbers together, and all the variables

3y+6(y+5)

We multiply parentheses

3y+6y+30

We add all the numbers together, and all the variables

9y+30

Back to the equation:

-(9y+30)



We add all the numbers together, and all the variables

-9y-(9y+30)-22=0

We get rid of parentheses

-9y-9y-30-22=0

We add all the numbers together, and all the variables

-18y-52=0

We move all terms containing y to the left, all other terms to the right

-18y=52

y=52/-18

y=-2+8/9

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