4x+1=2(x+1)+19

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Solution for 4x+1=2(x+1)+19 equation: 



4x+1=2(x+1)+19

We move all terms to the left:

4x+1-(2(x+1)+19)=0



We calculate terms in parentheses: -(2(x+1)+19), so:

2(x+1)+19

We multiply parentheses

2x+2+19

We add all the numbers together, and all the variables

2x+21

Back to the equation:

-(2x+21)



We get rid of parentheses

4x-2x-21+1=0

We add all the numbers together, and all the variables

2x-20=0

We move all terms containing x to the left, all other terms to the right

2x=20

x=20/2

x=10

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