(n/2)(13n-99)=0

Solution for (n/2)(13n-99)=0 equation:

(n/2)(13n-99)=0


Domain of the equation: 2)(13n-99)!=0

n∈R


We add all the numbers together, and all the variables

(+n/2)(13n-99)=0

We multiply parentheses ..

(+13n^2-99n)=0

We get rid of parentheses

13n^2-99n=0

a = 13; b = -99; c = 0;
Δ = b2-4ac
Δ = -992-4·13·0
Δ = 9801
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9801}=99$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-99)-99}{2*13}=\frac{0}{26}
=0
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-99)+99}{2*13}=\frac{198}{26}
=7+8/13
$