(m-3)(m-4)+10=0

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Solution for (m-3)(m-4)+10=0 equation: 



(m-3)(m-4)+10=0

We multiply parentheses ..

(+m^2-4m-3m+12)+10=0

We get rid of parentheses

m^2-4m-3m+12+10=0

We add all the numbers together, and all the variables

m^2-7m+22=0

a = 1; b = -7; c = +22;
Δ = b2-4ac
Δ = -72-4·1·22
Δ = -39
Delta is less than zero, so there is no solution for the equation

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