-3(2u-3)+3u=3(u+2)

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Solution for -3(2u-3)+3u=3(u+2) equation: 



-3(2u-3)+3u=3(u+2)

We move all terms to the left:

-3(2u-3)+3u-(3(u+2))=0

We add all the numbers together, and all the variables

3u-3(2u-3)-(3(u+2))=0

We multiply parentheses

3u-6u-(3(u+2))+9=0



We calculate terms in parentheses: -(3(u+2)), so:

3(u+2)

We multiply parentheses

3u+6

Back to the equation:

-(3u+6)



We add all the numbers together, and all the variables

-3u-(3u+6)+9=0

We get rid of parentheses

-3u-3u-6+9=0

We add all the numbers together, and all the variables

-6u+3=0

We move all terms containing u to the left, all other terms to the right

-6u=-3

u=-3/-6

u=1/2

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