(4x-3)+(9x+12)=(6x+3)

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Solution for (4x-3)+(9x+12)=(6x+3) equation: 



(4x-3)+(9x+12)=(6x+3)

We move all terms to the left:

(4x-3)+(9x+12)-((6x+3))=0

We get rid of parentheses

4x+9x-((6x+3))-3+12=0



We calculate terms in parentheses: -((6x+3)), so:

(6x+3)

We get rid of parentheses

6x+3

Back to the equation:

-(6x+3)



We add all the numbers together, and all the variables

13x-(6x+3)+9=0

We get rid of parentheses

13x-6x-3+9=0

We add all the numbers together, and all the variables

7x+6=0

We move all terms containing x to the left, all other terms to the right

7x=-6

x=-6/7

x=-6/7

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