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-2y^2+16y-24=0
a = -2; b = 16; c = -24;
Δ = b2-4ac
Δ = 162-4·(-2)·(-24)
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{64}=8$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(16)-8}{2*-2}=\frac{-24}{-4} =+6 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(16)+8}{2*-2}=\frac{-8}{-4} =+2 $
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