-2n+2n=2(1-4n)+7(n+2)

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Solution for -2n+2n=2(1-4n)+7(n+2) equation: 



-2n+2n=2(1-4n)+7(n+2)

We move all terms to the left:

-2n+2n-(2(1-4n)+7(n+2))=0

We add all the numbers together, and all the variables

-2n+2n-(2(-4n+1)+7(n+2))=0

We add all the numbers together, and all the variables

-(2(-4n+1)+7(n+2))=0



We calculate terms in parentheses: -(2(-4n+1)+7(n+2)), so:

2(-4n+1)+7(n+2)

We multiply parentheses

-8n+7n+2+14

We add all the numbers together, and all the variables

-1n+16

Back to the equation:

-(-1n+16)



We get rid of parentheses

1n-16=0

We add all the numbers together, and all the variables

n-16=0

We move all terms containing n to the left, all other terms to the right

n=16

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