2+3(3v-3)=-5(3v-1)+6v

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Solution for 2+3(3v-3)=-5(3v-1)+6v equation: 



2+3(3v-3)=-5(3v-1)+6v

We move all terms to the left:

2+3(3v-3)-(-5(3v-1)+6v)=0

We multiply parentheses

9v-(-5(3v-1)+6v)-9+2=0



We calculate terms in parentheses: -(-5(3v-1)+6v), so:

-5(3v-1)+6v

We add all the numbers together, and all the variables

6v-5(3v-1)

We multiply parentheses

6v-15v+5

We add all the numbers together, and all the variables

-9v+5

Back to the equation:

-(-9v+5)



We add all the numbers together, and all the variables

9v-(-9v+5)-7=0

We get rid of parentheses

9v+9v-5-7=0

We add all the numbers together, and all the variables

18v-12=0

We move all terms containing v to the left, all other terms to the right

18v=12

v=12/18

v=2/3

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