-5(4v-4)+8v=6(v+1)

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Solution for -5(4v-4)+8v=6(v+1) equation: 



-5(4v-4)+8v=6(v+1)

We move all terms to the left:

-5(4v-4)+8v-(6(v+1))=0

We add all the numbers together, and all the variables

8v-5(4v-4)-(6(v+1))=0

We multiply parentheses

8v-20v-(6(v+1))+20=0



We calculate terms in parentheses: -(6(v+1)), so:

6(v+1)

We multiply parentheses

6v+6

Back to the equation:

-(6v+6)



We add all the numbers together, and all the variables

-12v-(6v+6)+20=0

We get rid of parentheses

-12v-6v-6+20=0

We add all the numbers together, and all the variables

-18v+14=0

We move all terms containing v to the left, all other terms to the right

-18v=-14

v=-14/-18

v=7/9

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