-2b+2(b-1)=2(10+5b)

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Solution for -2b+2(b-1)=2(10+5b) equation: 



-2b+2(b-1)=2(10+5b)

We move all terms to the left:

-2b+2(b-1)-(2(10+5b))=0

We add all the numbers together, and all the variables

-2b+2(b-1)-(2(5b+10))=0

We multiply parentheses

-2b+2b-(2(5b+10))-2=0



We calculate terms in parentheses: -(2(5b+10)), so:

2(5b+10)

We multiply parentheses

10b+20

Back to the equation:

-(10b+20)



We add all the numbers together, and all the variables

-(10b+20)-2=0

We get rid of parentheses

-10b-20-2=0

We add all the numbers together, and all the variables

-10b-22=0

We move all terms containing b to the left, all other terms to the right

-10b=22

b=22/-10

b=-2+1/5

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