-25=5/9(f-32)

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Solution for -25=5/9(f-32) equation: 



-25=5/9(f-32)

We move all terms to the left:

-25-(5/9(f-32))=0



Domain of the equation: 9(f-32))!=0

f∈R



We multiply all the terms by the denominator


-(5-25*9(f-32))=0



We calculate terms in parentheses: -(5-25*9(f-32)), so:

5-25*9(f-32)

determiningTheFunctionDomain
-25*9(f-32)+5

Wy multiply elements

-225f(f+5

Back to the equation:

-(-225f(f+5)





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-225f(f+5





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-225f(f+5





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-225f(f+5





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-225f(f+5





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-225f(f+5





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-225f(f+5





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-225f(f+5





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-225f(f+5





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-225f(f+5





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-225f(f+5





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-225f(f+5





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