20+2(3x+10)=2x-3(3x+x)

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Solution for 20+2(3x+10)=2x-3(3x+x) equation: 



20+2(3x+10)=2x-3(3x+x)

We move all terms to the left:

20+2(3x+10)-(2x-3(3x+x))=0

We add all the numbers together, and all the variables

2(3x+10)-(2x-3(+4x))+20=0

We multiply parentheses

6x-(2x-3(+4x))+20+20=0



We calculate terms in parentheses: -(2x-3(+4x)), so:

2x-3(+4x)

We multiply parentheses

2x-12x

We add all the numbers together, and all the variables

-10x

Back to the equation:

-(-10x)



We add all the numbers together, and all the variables

6x-(-10x)+40=0

We get rid of parentheses

6x+10x+40=0

We add all the numbers together, and all the variables

16x+40=0

We move all terms containing x to the left, all other terms to the right

16x=-40

x=-40/16

x=-2+1/2

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