6(y+5)=-3(2y-5)+6y

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Solution for 6(y+5)=-3(2y-5)+6y equation: 



6(y+5)=-3(2y-5)+6y

We move all terms to the left:

6(y+5)-(-3(2y-5)+6y)=0

We multiply parentheses

6y-(-3(2y-5)+6y)+30=0



We calculate terms in parentheses: -(-3(2y-5)+6y), so:

-3(2y-5)+6y

We add all the numbers together, and all the variables

6y-3(2y-5)

We multiply parentheses

6y-6y+15

We add all the numbers together, and all the variables

15

Back to the equation:

-(15)



We add all the numbers together, and all the variables

6y+15=0

We move all terms containing y to the left, all other terms to the right

6y=-15

y=-15/6

y=-2+1/2

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