-24=2(c-12)+8c

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Solution for -24=2(c-12)+8c equation: 



-24=2(c-12)+8c

We move all terms to the left:

-24-(2(c-12)+8c)=0



We calculate terms in parentheses: -(2(c-12)+8c), so:

2(c-12)+8c

We add all the numbers together, and all the variables

8c+2(c-12)

We multiply parentheses

8c+2c-24

We add all the numbers together, and all the variables

10c-24

Back to the equation:

-(10c-24)



We get rid of parentheses

-10c+24-24=0

We add all the numbers together, and all the variables

-10c=0

c=0/-10

c=0

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