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-2/5x+5=20-x
We move all terms to the left:
-2/5x+5-(20-x)=0
Domain of the equation: 5x!=0We add all the numbers together, and all the variables
x!=0/5
x!=0
x∈R
-2/5x-(-1x+20)+5=0
We get rid of parentheses
-2/5x+1x-20+5=0
We multiply all the terms by the denominator
1x*5x-20*5x+5*5x-2=0
Wy multiply elements
5x^2-100x+25x-2=0
We add all the numbers together, and all the variables
5x^2-75x-2=0
a = 5; b = -75; c = -2;
Δ = b2-4ac
Δ = -752-4·5·(-2)
Δ = 5665
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-75)-\sqrt{5665}}{2*5}=\frac{75-\sqrt{5665}}{10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-75)+\sqrt{5665}}{2*5}=\frac{75+\sqrt{5665}}{10} $
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