2(3-x)-(3x+1)=4+7(x-5)

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Solution for 2(3-x)-(3x+1)=4+7(x-5) equation: 



2(3-x)-(3x+1)=4+7(x-5)

We move all terms to the left:

2(3-x)-(3x+1)-(4+7(x-5))=0

We add all the numbers together, and all the variables

2(-1x+3)-(3x+1)-(4+7(x-5))=0

We multiply parentheses

-2x-(3x+1)-(4+7(x-5))+6=0

We get rid of parentheses

-2x-3x-(4+7(x-5))-1+6=0



We calculate terms in parentheses: -(4+7(x-5)), so:

4+7(x-5)

determiningTheFunctionDomain
7(x-5)+4

We multiply parentheses

7x-35+4

We add all the numbers together, and all the variables

7x-31

Back to the equation:

-(7x-31)



We add all the numbers together, and all the variables

-5x-(7x-31)+5=0

We get rid of parentheses

-5x-7x+31+5=0

We add all the numbers together, and all the variables

-12x+36=0

We move all terms containing x to the left, all other terms to the right

-12x=-36

x=-36/-12

x=+3

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