-2(z-3)-z=-z-4(z+2)

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Solution for -2(z-3)-z=-z-4(z+2) equation: 



-2(z-3)-z=-z-4(z+2)

We move all terms to the left:

-2(z-3)-z-(-z-4(z+2))=0

We add all the numbers together, and all the variables

-1z-2(z-3)-(-z-4(z+2))=0

We multiply parentheses

-1z-2z-(-z-4(z+2))+6=0



We calculate terms in parentheses: -(-z-4(z+2)), so:

-z-4(z+2)

We add all the numbers together, and all the variables

-1z-4(z+2)

We multiply parentheses

-1z-4z-8

We add all the numbers together, and all the variables

-5z-8

Back to the equation:

-(-5z-8)



We add all the numbers together, and all the variables

-3z-(-5z-8)+6=0

We get rid of parentheses

-3z+5z+8+6=0

We add all the numbers together, and all the variables

2z+14=0

We move all terms containing z to the left, all other terms to the right

2z=-14

z=-14/2

z=-7

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