31=5(2-7k)+7(k+7)

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Solution for 31=5(2-7k)+7(k+7) equation:



31=5(2-7k)+7(k+7)
We move all terms to the left:
31-(5(2-7k)+7(k+7))=0
We add all the numbers together, and all the variables
-(5(-7k+2)+7(k+7))+31=0
We calculate terms in parentheses: -(5(-7k+2)+7(k+7)), so:
5(-7k+2)+7(k+7)
We multiply parentheses
-35k+7k+10+49
We add all the numbers together, and all the variables
-28k+59
Back to the equation:
-(-28k+59)
We get rid of parentheses
28k-59+31=0
We add all the numbers together, and all the variables
28k-28=0
We move all terms containing k to the left, all other terms to the right
28k=28
k=28/28
k=1

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