20(x+5)+4x+44=12(2x+12)

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Solution for 20(x+5)+4x+44=12(2x+12) equation: 



20(x+5)+4x+44=12(2x+12)

We move all terms to the left:

20(x+5)+4x+44-(12(2x+12))=0

We add all the numbers together, and all the variables

4x+20(x+5)-(12(2x+12))+44=0

We multiply parentheses

4x+20x-(12(2x+12))+100+44=0



We calculate terms in parentheses: -(12(2x+12)), so:

12(2x+12)

We multiply parentheses

24x+144

Back to the equation:

-(24x+144)



We add all the numbers together, and all the variables

24x-(24x+144)+144=0

We get rid of parentheses

24x-24x-144+144=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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