-2(z+3)-z=z+2-4(z+2)

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Solution for -2(z+3)-z=z+2-4(z+2) equation: 



-2(z+3)-z=z+2-4(z+2)

We move all terms to the left:

-2(z+3)-z-(z+2-4(z+2))=0

We add all the numbers together, and all the variables

-1z-2(z+3)-(z+2-4(z+2))=0

We multiply parentheses

-1z-2z-(z+2-4(z+2))-6=0



We calculate terms in parentheses: -(z+2-4(z+2)), so:

z+2-4(z+2)

determiningTheFunctionDomain
z-4(z+2)+2

We multiply parentheses

z-4z-8+2

We add all the numbers together, and all the variables

-3z-6

Back to the equation:

-(-3z-6)



We add all the numbers together, and all the variables

-3z-(-3z-6)-6=0

We get rid of parentheses

-3z+3z+6-6=0

We add all the numbers together, and all the variables

=0

z=0/1

z=0

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