7k+k2=+7k2

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Solution for 7k+k2=+7k2 equation:



7k+k2=+7k^2
We move all terms to the left:
7k+k2-(+7k^2)=0
We add all the numbers together, and all the variables
k^2-(+7k^2)+7k=0
We get rid of parentheses
k^2-7k^2+7k=0
We add all the numbers together, and all the variables
-6k^2+7k=0
a = -6; b = 7; c = 0;
Δ = b2-4ac
Δ = 72-4·(-6)·0
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{49}=7$
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-7}{2*-6}=\frac{-14}{-12} =1+1/6 $
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+7}{2*-6}=\frac{0}{-12} =0 $

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