4(u-4)-4=-4(-6u+1)-8u

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Solution for 4(u-4)-4=-4(-6u+1)-8u equation: 



4(u-4)-4=-4(-6u+1)-8u

We move all terms to the left:

4(u-4)-4-(-4(-6u+1)-8u)=0

We multiply parentheses

4u-(-4(-6u+1)-8u)-16-4=0



We calculate terms in parentheses: -(-4(-6u+1)-8u), so:

-4(-6u+1)-8u

We add all the numbers together, and all the variables

-8u-4(-6u+1)

We multiply parentheses

-8u+24u-4

We add all the numbers together, and all the variables

16u-4

Back to the equation:

-(16u-4)



We add all the numbers together, and all the variables

4u-(16u-4)-20=0

We get rid of parentheses

4u-16u+4-20=0

We add all the numbers together, and all the variables

-12u-16=0

We move all terms containing u to the left, all other terms to the right

-12u=16

u=16/-12

u=-1+1/3

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